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प्रश्न
Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:
y = x2 + 2x + C : y′ – 2x – 2 = 0
योग
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उत्तर
y = x2 + 2x + C
`dy/dx` = 2x + 2
⇒ `dy/dx` - 2x - 2 = 0
or y’ - 2x - 2 = 0
The given function is the solution of the given differential equation.
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