Advertisements
Advertisements
प्रश्न
The solution of the differential equation `("d"y)/("d"x) = "e"^(x - y) + x^2 "e"^-y` is ______.
विकल्प
y =`"e"^(x - y) = x^2 "e"^-y + "c"`
`"e"^y - "e"^x = x^3/3 + "c"`
`"e"^x + "e"^y = x^3/3 + "c"`
`"e"^x - "e"^y = x^3/3 + "c"`
MCQ
रिक्त स्थान भरें
Advertisements
उत्तर
The solution of the differential equation `("d"y)/("d"x) = "e"^(x - y) + x^2 "e"^-y` is `"e"^y - "e"^x = x^3/3 + "c"`.
Explanation:
The given differential equation is `("d"y)/("d"x) = "e"^(x - y) + x^2 "e"^-y`
⇒ `("d"y)/("d"x) = "e"^x . "e"^-y + x^2 . "e"^-y`
⇒ `("d"y)/("d"x) = "e"^-y ("e"^x + x^2)`
⇒ `("d"y)/"e"^-y = ("e"^x + x^2)"d"x`
⇒ `"e"^y . "d"y = ("e"^x + x^2)"d"x`
Integrating both sides, we have
`int "e"^x "d"y = int ("e"^x + x^2) "d"x`
⇒ `"e"^y = "e"^x + x^3/3 + "c"`
⇒ `"e"^y - "e"^x = x^3/3 + "c"`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
