हिंदी

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: y – cos y = x : (y sin y + cos y + x) y′ = y

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प्रश्न

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

y – cos y = x :  (y sin y + cos y + x) y′ = y

योग
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उत्तर

y - cos y = 3x

y’ + sin y : y’ = 1

y (1 + sin y) = 1

⇒ y’ = `1/(1 + sin y)`

Putting the values ​​of y' and y in the differential equation (y sin y + cos y + x) y’ = y

L.H.S. {(x + cos y) sin y + cosy + x}·  `1/(1 + sin y)`

⇒ x + cos y = y

R.H.S. Hence, the given function y - cos y = 3x is a solution of the given differential equation.

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अध्याय 9: Differential Equations - Exercise 9.2 [पृष्ठ ३८५]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 9 Differential Equations
Exercise 9.2 | Q 8 | पृष्ठ ३८५
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