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Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: y = Ax : xy′ = y (x ≠ 0) - Mathematics

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प्रश्न

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

y = Ax : xy′ = y (x ≠ 0)

योग
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उत्तर

We have, y = Ax                 ...(1)

Differentiating (1) w.r.t.x, we get,

y' = A                         ...(2)

Dividing (2) by (1), we get

`(y')/y = 1/x`

⇒ xy' = y

Hence, y = Ax is a solution of the given differential equation.

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अध्याय 9: Differential Equations - Exercise 9.2 [पृष्ठ ३८५]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 9 Differential Equations
Exercise 9.2 | Q 5 | पृष्ठ ३८५

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