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The solution of ddedydx+y=e-x, y(0) = 0 is ______. - Mathematics

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प्रश्न

The solution of `("d"y)/("d"x) + y = "e"^-x`, y(0) = 0 is ______.

विकल्प

  • y = ex(x – 1)

  • y = xe–x 

  • y = xe–x + 1

  • y = (x + 1)e–x 

MCQ
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उत्तर

The solution of `("d"y)/("d"x) + y = "e"^-x`, y(0) = 0 is y = xe–x .

Explanation:

The given differential equation is `("d"y)/("d"x) + y = "e"^-x`

Since, it is a linear differential equation

∴ P = 1 and Q = e–x

∴ I.F = `"e"^(int 1."d"x)` = ex

So, the solution is `y xx "I"."F". = int "Q". "I"."F". "d"x + "c"`

⇒ `y . "e"^x = int"e"^-x . "e"^x "d"x + "c"`

⇒ `y . "e"^x = int 1."d"x + "c"`

⇒ `y . "e"^x + "c"`

Put x = 0, y = 0

We have 0 = 0 + c

∴ c = 0

So, the solution is `y "e"^x` = x

⇒ y = `x . "e"^-x`

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अध्याय 9: Differential Equations - Exercise [पृष्ठ १९७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 52 | पृष्ठ १९७

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