हिंदी

The General Solution of the Differential Equation D Y D X = Y X is

Advertisements
Advertisements

प्रश्न

The general solution of the differential equation \[\frac{dy}{dx} = \frac{y}{x}\] is

विकल्प

  • log y = kx

  • y = kx

  • xy = k

  • y = k log x

MCQ
Advertisements

उत्तर

y = kx

 

We have,
\[\frac{dy}{dx} = \frac{y}{x}\]
\[ \Rightarrow \frac{1}{y}dy = \frac{1}{x}dx\]
Integrating both sides, we get
\[\int\frac{1}{y}dy = \int\frac{1}{x}dx\]
\[ \Rightarrow \log y = \log x + \log k\]
\[ \Rightarrow \log y - \log x = \log k\]
\[ \Rightarrow \log\left( \frac{y}{x} \right) = \log k\]
\[ \Rightarrow \frac{y}{x} = k\]
\[ \Rightarrow y = kx\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 21: Differential Equations - MCQ [पृष्ठ १३९]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 21 Differential Equations
MCQ | Q 2 | पृष्ठ १३९

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Form the differential equation of the family of circles in the second quadrant and touching the coordinate axes.


Find the particular solution of the differential equation

(1 – y2) (1 + log x) dx + 2xy dy = 0, given that y = 0 when x = 1.


If y = P eax + Q ebx, show that

`(d^y)/(dx^2)=(a+b)dy/dx+aby=0`


Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

y = cos x + C : y′ + sin x = 0


Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

y = Ax : xy′ = y (x ≠ 0)


Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

x + y = tan–1y   :   y2 y′ + y2 + 1 = 0


The number of arbitrary constants in the general solution of a differential equation of fourth order are ______.


The number of arbitrary constants in the particular solution of a differential equation of third order are ______.


Find a particular solution of the differential equation`(x + 1) dy/dx = 2e^(-y) - 1`, given that y = 0 when x = 0.


Find `(dy)/(dx)` at x = 1, y = `pi/4` if `sin^2 y + cos xy = K`


The general solution of the differential equation \[\frac{dy}{dx} + y\] g' (x) = g (x) g' (x), where g (x) is a given function of x, is


The solution of the differential equation \[2x\frac{dy}{dx} - y = 3\] represents


The solution of x2 + y \[\frac{dy}{dx}\]= 4, is


The solution of the differential equation \[\frac{dy}{dx} = \frac{x^2 + xy + y^2}{x^2}\], is


Solve the differential equation (x2 − yx2) dy + (y2 + x2y2) dx = 0, given that y = 1, when x = 1.


cos (x + y) dy = dx


(x + y − 1) dy = (x + y) dx


\[\frac{dy}{dx} - y \tan x = - 2 \sin x\]


Solve the differential equation:

(1 + y2) dx = (tan1 y x) dy


For the following differential equation, find a particular solution satisfying the given condition:

\[x\left( x^2 - 1 \right)\frac{dy}{dx} = 1, y = 0\text{ when }x = 2\]


Solve the following differential equation:-

\[\frac{dy}{dx} + \left( \sec x \right) y = \tan x\]


Solve the differential equation:  ` ("x" + 1) (d"y")/(d"x") = 2e^-"y" - 1; y(0) = 0.`


Find the differential equation of all non-horizontal lines in a plane.


The general solution of the differential equation `"dy"/"dx" = "e"^(x - y)` is ______.


Find the general solution of `(x + 2y^3)  "dy"/"dx"` = y


Find the general solution of y2dx + (x2 – xy + y2) dy = 0.


Solve the differential equation dy = cosx(2 – y cosecx) dx given that y = 2 when x = `pi/2`


Solve the differential equation (1 + y2) tan–1xdx + 2y(1 + x2)dy = 0.


Solve: `y + "d"/("d"x) (xy) = x(sinx + logx)`


If y = e–x (Acosx + Bsinx), then y is a solution of ______.


The differential equation for y = Acos αx + Bsin αx, where A and B are arbitrary constants is ______.


Solution of differential equation xdy – ydx = 0 represents : ______.


Solution of the differential equation `("d"y)/("d"x) + y/x` = sec x is ______.


The solution of the differential equation `("d"y)/("d"x) + (2xy)/(1 + x^2) = 1/(1 + x^2)^2` is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×