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tan x + tan ( π 3 + x ) − tan ( π 3 − x ) = 3 tan 3 x - Mathematics

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प्रश्न

\[\tan x + \tan\left( \frac{\pi}{3} + x \right) - \tan\left( \frac{\pi}{3} - x \right) = 3 \tan 3x\] 

संख्यात्मक
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उत्तर

\[\frac{\pi}{3} = 60°\]
\[LHS = \text{ tan } x + \tan\left( 60° + x \right) - \tan\left( 60° - x \right)\]
\[ = \text{ tan } x + \left( \frac{\tan60°  + \text { tan } x}{1 - \tan60°  \text{ tan } x} \right) - \left( \frac{\tan60°  - \text{ tan } x}{1 + \tan60°  \text{ tan } x} \right)\]
\[ \left[ \tan\left( x + y \right) = \frac{\text{ tan } x + \text{ tan } y}{1 - \text{ tan } x \text{ tan } y} \text{ and }  \tan\left( x - y \right) = \frac{\text{ tan } x - \text{ tan } y}{1 + \text{ tan } x \text{ tan } y} \right]\]
\[ = \text{ tanx }  + \frac{\sqrt{3} + \text{ tan } x}{1 - \sqrt{3} \text{ tan } x} - \frac{\sqrt{3} - \text{ tan } x}{1 + \sqrt{3} \text{ tan } x}\]
\[ = \text{ tan } x + \frac{\sqrt{3} + 3\text{ tan } x + \text{ tan } x + \sqrt{3} \tan^2 x + \sqrt{3} + 3\text{ tan } x + \text{ tan } x - \sqrt{3} \tan^2 x}{\left( 1 - \sqrt{3} \text{ tan } x \right)\left( 1 + \sqrt{3} \text{ tan } x \right)}\]
\[ = \text{ tan } x + \frac{8\text{ tan } x}{1 - 3 \tan^2 x}\] 

\[= \frac{\text{ tan } x - 3 \tan^3 x + 8\text{ tan } x}{1 - 3 \tan^2 x}\]
\[ = \frac{9\text{ tan } x - 3 \tan^3 x}{1 - 3 \tan^2 x}\]
\[ = 3\left( \frac{3\text{ tan } x - \tan^3 x}{1 - 3 \tan^2 x} \right) \left( \because \tan3\theta = \frac{3tan\theta - \tan^3 \theta}{1 - 3 \tan^2 \theta} \right) \]
\[ = 3\tan3x\]
\[ = RHS\]
\[\text{ Hence proved .}  \]

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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अध्याय 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.2 [पृष्ठ ३६]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.2 | Q 5 | पृष्ठ ३६

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