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Prove That: Cos 2 π 15 Cos 4 π 15 Cos 8 π 15 Cos 16 π 15 = 1 16 - Mathematics

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प्रश्न

Prove that: \[\cos\frac{2\pi}{15} \cos\frac{4\pi}{15} \cos \frac{8\pi}{15} \cos \frac{16\pi}{15} = \frac{1}{16}\]

संख्यात्मक
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उत्तर

\[LHS = \cos\frac{2\pi}{15} \cos\frac{4\pi}{15} \cos\frac{8\pi}{15} \cos\frac{16\pi}{15}\] On dividing and multiplying by  \[2\sin\frac{2\pi}{15}\] , we get
\[= \frac{1}{2\sin\frac{2\pi}{15}} \times \left( 2\sin\frac{2\pi}{15} \times \cos\frac{2\pi}{15} \right) \times \cos\frac{4\pi}{15} \times \cos\frac{8\pi}{15} \times \cos\frac{16\pi}{15}\]
\[ = \frac{1}{2 \times 2\sin\frac{2\pi}{15}} \times \left( 2\sin\frac{4\pi}{15} \times \cos\frac{4\pi}{15} \right) \times \cos\frac{8\pi}{15} \times \cos\frac{16\pi}{15} \]
\[ = \frac{1}{2 \times 4\sin\frac{2\pi}{15}}\left( 2\sin\frac{8\pi}{15} \times \cos\frac{8\pi}{15} \right) \times \cos\frac{16\pi}{15}\]
\[ = \frac{1}{2 \times 8\sin\frac{2\pi}{15}}\left( 2\sin\frac{16\pi}{15} \times \cos\frac{16\pi}{15} \right)\]
\[ = \frac{1}{16\sin\frac{2\pi}{15}}\left( \sin\frac{32\pi}{15} \right)\]

\[= - \frac{1}{16\sin\frac{2\pi}{15}}\left( \sin2\pi - \frac{32\pi}{15} \right) \left[ \because \sin\left( 2\pi - \theta \right) = - sin\theta \right]\]
\[ = - \frac{1}{16\sin\frac{2\pi}{15}}\sin\left( - \frac{2\pi}{15} \right)\]
\[ = \frac{1}{16} = RHS\]
\[\text{ Hence proved } .\]

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.1 [पृष्ठ २९]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.1 | Q 34 | पृष्ठ २९

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