हिंदी

If tanA = BB1-cosBsinB, then tan2A = ______.

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प्रश्न

If tanA = `(1 - cos "B")/sin"B"`, then tan2A = ______.

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उत्तर

Given that: tanA = `(1 - cos "B")/sin"B"`

tan2A = `(2tan"A")/(1 - tan^2"A")`

= `(2((1 - cos "B")/sin"B"))/(1 - ((1 - cos "B")/sin"B")^2`

= `(2((2sin^2  "B"/2)/(2sin  "B"/2 cos  "B"/2)))/(1 - ((2sin^2  "B"/2)/(2sin  "B"/2 cos  "B"/2))^2`   ........`[(because 1 - cos "B" = 2sin^2  "B"/2),(sin"B" = 2sin"B"/2 cos"B"/2)]`

= `(2((sin  "B"/2)/(cos  "B"/2)))/(1 - ((sin  "B"/2)/(cos  "B"/2))^2`

= `(2tan  "B"/2)/(1 - tan^2  "B"/2)`

= tanB

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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अध्याय 3: Trigonometric Functions - Exercise [पृष्ठ ५९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
अध्याय 3 Trigonometric Functions
Exercise | Q 62 | पृष्ठ ५९

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