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If Tan α = 1 7 , Tan β = 1 3 , Then Cos 2 α is Equal to - Mathematics

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प्रश्न

If \[\tan\alpha = \frac{1}{7}, \tan\beta = \frac{1}{3}\], then

\[\cos2\alpha\]   is equal to

 

विकल्प

  • \[\sin2\beta\]

  • \[\sin4\beta\]

     

  • \[\sin3\beta\]

     

  • \[\cos2\beta\]

     

MCQ
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उत्तर

It is given that \[\tan\alpha = \frac{1}{7}\]  and \[\tan\beta = \frac{1}{3}\]

Now,

\[\tan2\beta = \frac{2\tan\beta}{1 - \tan^2 \beta}\]

\[ = \frac{2 \times \frac{1}{3}}{1 - \frac{1}{9}}\]

\[ = \frac{\frac{2}{3}}{\frac{8}{9}}\]

\[ = \frac{3}{4}\]

\[\therefore \tan\left( \alpha + 2\beta \right) = \frac{\tan\alpha + \tan2\beta}{1 - \tan\alpha \tan2\beta}\]
\[ = \frac{\frac{1}{7} + \frac{3}{4}}{1 - \frac{1}{7} \times \frac{3}{4}}\]
\[ = \frac{\frac{25}{28}}{\frac{25}{28}}\]
\[ = 1\]

\[\tan\left( \alpha + 2\beta \right) = 1 = \tan\frac{\pi}{4}\]

\[ \Rightarrow \alpha + 2\beta = \frac{\pi}{4}\]

\[ \Rightarrow \alpha = \frac{\pi}{4} - 2\beta\]

\[ \Rightarrow 2\alpha = \frac{\pi}{2} - 4\beta\]

\[ \Rightarrow \cos2\alpha = \cos\left( \frac{\pi}{2} - 4\beta \right) = \sin4\beta\]

\[\therefore \cos2\alpha = \sin4\beta\]

 

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.5 [पृष्ठ ४५]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.5 | Q 37 | पृष्ठ ४५

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