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If Tan X = T Then Tan 2 X + Sec 2 X = - Mathematics

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प्रश्न

If \[\tan x = t\] then \[\tan 2x + \sec 2x =\]

 

विकल्प

  • \[\frac{1 + t}{1 - t}\]

     

  • \[\frac{1 - t}{1 + t}\]

     

  • \[\frac{2t}{1 - t}\]

     

  • \[\frac{2t}{1 + t}\]

     

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उत्तर

\[\frac{1 + t}{1 - t}\] 

\[\tan 2x + \sec 2x = \frac{2 \tan x}{1 - \tan^2 x} + \frac{1 + \tan^2 x}{1 - \tan^2 x}\]
\[ = \frac{2\tan x + 1 + \tan^2 x}{1 - \tan^2 x}\]
\[ = \frac{\left( 1 + \tan x \right)^2}{1 - \tan^2 x}\]
\[ = \frac{\left( 1 + \tan x \right)\left( 1 + \tan x \right)}{\left( 1 + \tan x \right)\left( 1 - \tan x \right)}\]
\[ = \frac{1 + \tan x}{1 - \tan x}\]
\[ = \frac{1 + t}{1 - t} \left[ \tan x = t \left( \text{ given } \right) \right]\]

 

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.5 [पृष्ठ ४५]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.5 | Q 28 | पृष्ठ ४५

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