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If A = cos2θ + sin4θ for all values of θ, then prove that 34 ≤ A ≤ 1. - Mathematics

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प्रश्न

If A = cos2θ + sin4θ for all values of θ, then prove that `3/4` ≤ A ≤ 1.

योग
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उत्तर

We have A = cos2θ + sin4θ

= cos2θ + sin2θ sin2θ ≤ cos2θ + sin2θ

Therefore, A ≤ 1

Also, A = cos2θ + sin4θ

= (1 – sin2θ) + sin4θ

= `(sin^2theta - 1/2)^2 + (1 - 1/4)`

= `(sin^2theta - 1/2)^2 + 3/4 > 3/4`

Hence, `3/4 < "A" < 1`.

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Solved Examples [पृष्ठ ४०]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
Solved Examples | Q 2 | पृष्ठ ४०

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