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A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 cm. Find the angle in degrees which is subtended at the centre of hoop. - Mathematics

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प्रश्न

A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 cm. Find the angle in degrees which is subtended at the centre of hoop.

योग
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उत्तर

Given that circular wire is of radius 3 cm

So when it is cut then its length = 2π × 3 = 6π cm.

Again, it is being placed along a circular hoop of radius 48 cm.

Here, s = 6π cm is the length of arc and r = 48 cm is the radius of the circle.

Therefore, the angle θ, in radian, subtended by the arc at the centre of the circle is given by

θ = `"Arc"/"Radius"`

= `(6pi)/48`

= `pi/8`

= 22.5°.

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अध्याय 3: Trigonometric Functions - Solved Examples [पृष्ठ ३९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
Solved Examples | Q 1 | पृष्ठ ३९

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