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If tan(A + B) = p, tan(A – B) = q, then show that tan 2A = p+q1-pq - Mathematics

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प्रश्न

If tan(A + B) = p, tan(A – B) = q, then show that tan 2A = `(p + q)/(1 - pq)`

प्रमेय
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उत्तर

Given that: tan(A + B) = p, tan(A – B) = q

tan 2A = tan(A + B + A – B)

= tan[(A + B) + (A – B)]

= `(tan(A + B) + tan(A - B))/(1 - tan(A + B).tan(A - B))`

= `(p + q)/(1 - pq)`

Hence proved.

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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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अध्याय 3: Trigonometric Functions - Exercise [पृष्ठ ५३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 3 Trigonometric Functions
Exercise | Q 11 | पृष्ठ ५३

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