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प्रश्न
Resonance is a special case of ______ vibrations, when frequency of the driving force is ______ natural frequency of the body.
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उत्तर
Resonance is a special case of forced vibrations, when frequency of the driving force is equal to the natural frequency of the body.
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संबंधित प्रश्न
Name the phenomenon involved in tunning a radio set to a particular station
Define the Resonance phenomenon?
What are mechanical waves?
In following figure shows A, B, C and D are four pendulums suspended from the same elastic string XY. Lengths of pendulum A and D are equal, while the length of pendulum B is smaller and the pendulum C is longer. The pendulum A is set into vibration.
(a) what is your observation? (b) Give reason for your observation.

A tuning fork of frequency 256 Hz will resonate with another tuning fork of frequency:
In fig. , P, Q, R and S represent test tubes each of height 20 cm which are filled with water upto heights of 10 cm, 14 cm, 16 cm and 18 cm respectively. If a vibrating tuning fork is placed over the mouth of test tube Q, a loud sound is heard.
(i) Describe the observations with the tubes P, R and S.
(ii) Give the reason for your observation in each case.
(iii) State the principle illustrated by the above experiment.

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Free and forced vibrations.
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Explain a person walking past a railway line, in the middle of night hears a ringing sound along with the sound of his footsteps.
