Advertisements
Advertisements
प्रश्न
A tuning fork of frequency 256 Hz will resonate with another tuning fork of frequency:
विकल्प
128 Hz
256 Hz
384 Hz
512 Hz
Advertisements
उत्तर
A tuning fork of frequency 256 Hz will resonate with another tuning fork of frequency 256 Hz.
Hint: Resonance occurs when the frequency of an externally applied periodic force on the body is equal to its natural frequency.
संबंधित प्रश्न
Name the phenomenon involved in tunning a radio set to a particular station
What are forced vibrations?
Describe a simple experiment to illustrate the phenomenon of resonance and explain it.
In following figure shows two tuning forks A and B of the same frequency mounted on two separate sound boxes with their open ends facing each other. The fork A is set into vibration.
- Describe your observation.
- State the principle illustrated by this experiment.

In following figure shows A, B , C and D represent test tube each of height 20 cm which are filled with water up to heights of 12 cm, 14 cm, 16cm and 18cm respectively. If a vibrating tuning fork is placed over the mouth if test tube D, a loud sound is heard.

- Describe the observations with the tubes A, B and C when the vibrating tuning fork is placed over the mouth of these tubes.
- Give the reason for your observation in each case.
- State the principle illustrated by the above experiment.
When a troop crosses a suspension bridge, the soldiers are asked to break steps. Explain the reason.
Why are the stringed instruments like guitar provided with a hollow sound box?
On keeping the stem of a vibrating tuning fork on the surface of a table, a loud sound is heard. Give reason.
What do you understand by forced vibrations?
When the stem of vibrating tuning fork is pressed on a table, the tabletop starts vibrating. These vibrations are definitely an example of ______.
