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प्रश्न
A tuning fork of frequency 256 Hz will resonate with another tuning fork of frequency:
विकल्प
128 Hz
256 Hz
384 Hz
512 Hz
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उत्तर
A tuning fork of frequency 256 Hz will resonate with another tuning fork of frequency 256 Hz.
Hint: Resonance occurs when the frequency of an externally applied periodic force on the body is equal to its natural frequency.
संबंधित प्रश्न
Distinguish between the free (or natural) and forced vibrations.
In following figure shows two tuning forks A and B of the same frequency mounted on two separate sound boxes with their open ends facing each other. The fork A is set into vibration.
- Describe your observation.
- State the principle illustrated by this experiment.
Why are the stringed instruments like guitar provided with a hollow sound box?
Differentiate between the following:
Radio waves and light waves.
When acoustic resonance takes place, a loud sound is heard. Why does this happen? Explain.
The rearview mirror of a motorbike starts vibrating violently at some particular speed of the motorbike, what could be done to stop the violent vibrations.
When a tuning fork, struck by a rubber pad, is held over a length of the air column in a tube, it produces a loud sound for a fixed length of the air column. Name the above phenomenon. How does the frequency of the loud sound compare with that of the tuning fork? State the unit for measuring loudness.
Explain Why are stringed musical instruments provided with large sound boxes?
What do you understand by free vibrations of a body? Draw a displacement-time graph to represent them. Given one example.
