Advertisements
Advertisements
प्रश्न
In following figure shows two tuning forks A and B of the same frequency mounted on two separate sound boxes with their open ends facing each other. The fork A is set into vibration.
- Describe your observation.
- State the principle illustrated by this experiment.

Advertisements
उत्तर
- The vibrating tuning fork A produces the forced vibrations in the air column of its sound box. These vibrations are of large amplitude because of the large surface area of air in the sound box. They are communicated to the sound box of the fork B. The air column of B starts vibrating with the frequency of the fork A. Since the frequency of these vibrations is same as the natural frequency of the fork B, the fork B picks up these vibrations and starts vibrating due to resonance.
- On putting the tuning fork A to vibrate, the other tuning fork B will also start vibrating. The vibrations produced in the second tuning fork B are due to resonance.
APPEARS IN
संबंधित प्रश्न
Name the phenomenon involved in tunning a radio set to a particular station
What are mechanical waves?
What are forced vibrations?
Distinguish between the free (or natural) and forced vibrations.
When a body vibrates under a periodic force, the vibrations of the body are ______.
In fig. , P, Q, R and S represent test tubes each of height 20 cm which are filled with water upto heights of 10 cm, 14 cm, 16 cm and 18 cm respectively. If a vibrating tuning fork is placed over the mouth of test tube Q, a loud sound is heard.
(i) Describe the observations with the tubes P, R and S.
(ii) Give the reason for your observation in each case.
(iii) State the principle illustrated by the above experiment.

Explain why stringed musical instruments, like the guitar, are provided with a hollow box.
Explain Why are stringed musical instruments provided with large sound boxes?
What do you understand by forced vibrations?
