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प्रश्न
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
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उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y = x - 2 | -3 | -2 | -1 |
| Y = 2x + 1 | -1 | 1 | 3 |
| Y = 4 | 4 | 4 | 4 |
Now the graph can be drawn as follows:
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
x = 3
Draw the graph for the linear equation given below:
x + 3 = 0
Draw the graph for the linear equation given below:
2x - 7 = 0
Draw the graph for the linear equation given below:
4x - y = 0
Draw the graph for the linear equation given below:
y = 2x + 3
Draw the graph for the linear equation given below:
y = - x + 4
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
