Advertisements
Advertisements
प्रश्न
Draw a graph of each of the following equations: x + 6y = 15
Advertisements
उत्तर
x + 6y = 15
⇒ x = 15 - 6y
When y = 1, x = 15 - 6(1) = 9
When y =2, x = 15 - 6(2) = 3
When y = 3, x = 15 - 6(3) = -3
| x | 9 | 3 | -3 |
| y | 1 | 2 | 3 |
Plotting the points (9, 1), (3, 2) and (-3, 3), we get the line segment as shown in the figure.
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
x + 2y = 0
Draw the graph for the linear equation given below:
y = 2x + 3
Draw the graph for the equation given below:
2x - 5y = 10
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = x - 3
y = - x + 5
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw the graph of the lines represented by the equations 2x - y = 8 and 4x + 3y = 6 on the same graph. Find the co-ordinates of the point where they intersect.
