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प्रश्न
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
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उत्तर
The equation will become:
2x - 3y = 8
First prepare a table as follows:
| x | -1 | 0 | 1 |
| y | `-(10)/(3)` | `-(8)/(3)` | -2 |
Thus the graph can be drawn as follows:
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संबंधित प्रश्न
Draw the graph of the equation given below.
2x + y = 1
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x = 3
Draw the graph for the linear equation given below:
y = 3x
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x = - 2y
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
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For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
The graph of 3x + 2y = 6 meets the x=axis at point P and the y-axis at point Q. Use the graphical method to find the co-ordinates of points P and Q.
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: 3x - 2y = 6
