Advertisements
Advertisements
प्रश्न
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
Advertisements
उत्तर
`(2x)/(5) + y/(2)` = 1
⇒ `y/(2) = 1 - (2x)/(5)`
⇒ `y/(2) = (5 - 2x)/(5)`
⇒ y = `(10 - 4x)/(5)`
When x = 0, y = `(10 - 4(0))/(5)` = 2
When x = 5, y = `(10 - 4(5))/(5)` = -2
When x = `(5)/(2), y = (10 - 4(5/2))/(5)` = 0
| x | 0 | 5 | `(5)/(2)` |
| y | 2 | -2 | 0 |
Plotting the points (0, 2), (5, -2) and `(5/2 , 0)`, we get a line segment as shown in the figure.
The line meets the x-axis at `(5/2, 0)` and y-axis at (0, 2).
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
x = 0
Draw the graph for the linear equation given below:
4x - y = 0
Draw the graph for the linear equation given below:
y = 2x + 3
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
