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प्रश्न
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
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उत्तर
`(x - 2)/(3) - (y + 1)/(2)` = 0
⇒ `(x - 2)/(3) - (y + 1)/(2)`
⇒ 2(x - 2) = 3(y + 1)
= 2x - 4 = 3y + 3
⇒ 3y = 2x - 7
⇒ y = `(2x - 7)/(3)`
When x = 2, y = `(2(2) - 7)/(3)` = -1
When x = -1, y = `(2(-1) - 7)/(3)` = -3
When x = -2.5, y = `(2(-2.5) - 7)/(3)` = 4
| x | 2 | -1 | -2.5 |
| y | -1 | -3 | -4 |
Plotting the points (2, -1), (-1, -3) and (-2.5, -4), we get a line AB as shown in the figure.
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
y - 2 = 0
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For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: 3y + 2x = 11
Draw a graph of each of the following equations: 5x + 2y = 16
