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प्रश्न
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
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उत्तर
2(x - 5) = `(3)/(4)(y - 1)`
⇒ 8(x - 5) = 3(y - 1)
⇒ 8x - 40 = 3y - 3
⇒ 3y = 8x - 40 + 3
⇒ 3y = 8x - 37
y = `(8x - 37)/(3)`
When x = 2, = `(8(2) - 37)/(3)` = -7
When x = 5, y = `(8(5) - 37)/(3)` = 1
When x = -1, y = `(8(-1) - 37)/(3)` = -15
| x | 2 | 5 | -1 |
| y | -7 | 1 | -15 |
Plotting the points (2, -7), (5, 1) and (-1, -15), we get a line AB as shown in the figure.
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
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x = 0
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y = `4x - (5)/(2)`
Draw the graph for the linear equation given below:
2x - 3y = 4
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For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
Draw the graph of the equation 3x - 4y = 12.
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(i) y1, the value of y, when x = 4.
(ii) y2, the value of y, when x = 0.
Draw a graph of each of the following equations: 3y + 2x = 11
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: 2x + 3y = 12
