Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
y = - x
Advertisements
उत्तर
First prepare a table as follows:
| x | - 1 | 0 | 1 |
| y | 1 | 0 | - 1 |
Thus the graph can be drawn as follows:

APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
2x + y = 1
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
y = - 2x
Draw the graph for the linear equation given below:
4x - y = 0
Draw the graph for the linear equation given below:
y = - x + 4
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
Draw the graph for the equation given below:
2x - 5y = 10
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
