Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
y = - x
Advertisements
उत्तर
First prepare a table as follows:
| x | - 1 | 0 | 1 |
| y | 1 | 0 | - 1 |
Thus the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
2y - 5 = 0
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: 3x - 2y = 6
Draw a graph of each of the following equations: y = `(5)/(2) xx + (2)/(5)`
Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
(ii) y, when x = 2
