Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
y = 3x
Advertisements
उत्तर
First, prepare a table as follows:
| x | - 1 | 0 | 1 |
| y | - 3 | 0 | 3 |
Thus the graph can be drawn as follows:

APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
y = x
Draw the graph for the linear equation given below:
3x + 2y = 0
Draw the graph for the linear equation given below:
y = - x + 4
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw a graph of each of the following equations: 3x - 2y = 6
