Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
y = - 2x
Advertisements
उत्तर
First prepare a table as follows:
| x | - 1 | 0 | 1 |
| y | 2 | 0 | - 2 |
Thus the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph of the equation given below.
2x + y = 1
Draw the graph for the linear equation given below:
x + 2y = 0
Draw the graph for the linear equation given below:
3x + 2y = 0
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: 2x + 3y = 12
Draw the graph of the lines represented by the equations x + y = 4 and 2x - y = 2 on the same graph. Find the coordinates of the point where they intersect
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
