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प्रश्न
Draw the graph of the lines represented by the equations 5y = 3x + 1 and y = 2x + 3 on the same graph. Find the coordinates of the point where they intersect.
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उत्तर
For equation (1),
5y = 3x + 1
y = `(3x + 1)/(5)`
When x = -2,
y = `(3(-2) + 1)/(5)` = -1
When x = 8,
y = `(3(8) + 1)/(5)` = 5
When x = -7,
y = `(3(-7) + 1)/(5)` = -4
| x | -2 | 8 | -7 |
| y | -1 | 5 | -4 |
For equation (2),
y = 2x + 3
When x = 0, y = 2(0) + 3 = 3
When x = -1, y = 2(-1) + 3 = 1
When x = -7, y = 2(-7) + 3 = -11
| x | 0 | -1 | -7 |
| y | 3 | 1 | -11 |
(-2, -1)
∴ The point of intersection of the 2 lines is (-2, -1).
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संबंधित प्रश्न
Draw the graph of the equation given below.
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x - 5 = 0
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Draw the graph for the equation given below:
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Draw the graph for the equation given below:
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For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
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Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
