Advertisements
Advertisements
प्रश्न
Draw the graph of the lines represented by the equations 2x - y = 8 and 4x + 3y = 6 on the same graph. Find the co-ordinates of the point where they intersect.
Advertisements
उत्तर
We have
2x - y = 8
⇒ -y = 8 - 2x
⇒ y = 2x - 8
When
x = -2
⇒ y = -4 - 8
= -12
When
x = 0
⇒ y = -8
When
x = 2
⇒ y = 4 - 8
= -4
| x | -2 | -1 | 0 | 1 | 2 |
| y | -12 | -10 | -8 | -6 | -4 |
Thus ordered pairs of 2x - y = 8 are {(-2, -12), (-1, -10), (0, -8), (1, -6), (2, -4)}.
Also,
4x + 3y = 6
⇒ 3y = 6 - 4x
⇒ y = `(6 - 4x)/(3)`
When x = -2
⇒ y = `(6 + 8)/(3)` = 4.66
When x = 0
⇒ y = `(6)/(3)` = 2
When x = 2
⇒ y = `(6 - 8)/(3)` = -0.66
| x | -2 | -1 | 0 | 1 | 2 |
| y | 4.66 | 3.33 | 2 | 0.66 | -0.66 |
Thus ordered pairs of 4x + 3y = 6 are {(-2, 4.66), (-1, 3.33), (0.2), (1, 0.66), (2, -0.66)}.
The point of intersection is (3, -2).
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
2x + y = 1
The following table gives production yield in kg per hectare of wheat of 100 farms of a village:
| Production yield (kg/hectare): |
40 – 45 | 45 – 50 | 50 – 55 | 55 – 60 | 60 – 65 | 65 – 70 |
| Number of farms | 4 | 6 | 16 | 20 | 30 | 24 |
Change the distribution to 'a more than' type distribution, and draw its ogive.
Draw the graph for the linear equation given below:
x + 3 = 0
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
y = 3x
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
The graph of 3x + 2y = 6 meets the x=axis at point P and the y-axis at point Q. Use the graphical method to find the co-ordinates of points P and Q.
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw a graph of each of the following equations: y = `(5)/(2) xx + (2)/(5)`
