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प्रश्न
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
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उत्तर
We have
3x - y = 7
⇒ -y = 7 - 3x
⇒ y = 3x - 7
When x = -2
⇒ y = -6 - 7
= -13
When x = 0
⇒ y = -7
When x = 2
⇒ y = 6 - 7
= -1
| x | -2 | -1 | 0 | 1 | 2 |
| y | -13 | -10 | -7 | -7 | -1 |
Thus ordered pairs of 3x - y = 7 are {(-2, -13), (-1, -10), (0, -7), (1, -4), (2, -1)}. Hence graph is as below.
(i) y, when x = 1
From graph we find that y = -4, when x = 1
(ii) x, when y = 8
From graph we find that x = 5, when y = 8.
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
y = - x + 4
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
