Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
y = - x + 4
Advertisements
उत्तर
First, prepare a table as follows:
| x | -1 | 0 | 1 |
| y | 5 | 4 | 3 |
Thus the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
x = - 2y
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
