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प्रश्न
Draw the graph for the linear equation given below:
y = - x + 4
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उत्तर
First, prepare a table as follows:
| x | -1 | 0 | 1 |
| y | 5 | 4 | 3 |
Thus the graph can be drawn as follows:
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संबंधित प्रश्न
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
y = 0
Draw the graph for the linear equation given below:
5x+ y = 0.
Draw the graph for the linear equation given below:
y = 2x + 3
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
