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प्रश्न
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
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उत्तर
The equations can be written as follows:
y = 2 - x
y = `(1)/(2)(x - 5)`
y = `- x/(3)`
First prepare a table as follows:
| X | Y = 2 - x | Y = `(1)/(2)(x - 5)` | Y = `-x/(3)` |
| - 1 | 3 | - 3 | `(1)/(3)` |
| 0 | 2 | `-(5)/(2)` | 0 |
| 1 | 1 | - 2 | `-(1)/(3)` |
Thus the graph can be drawn as follows:

From the graph it is clear that the equation of lines are passes through the same point.
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संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph of the equation given below.
3x - y = 0
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
5x+ y = 0.
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw a graph of each of the following equations: 3y + 2x = 11
Draw a graph of each of the following equations: y = `(5)/(2) xx + (2)/(5)`
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
(ii) y, when x = 2
