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प्रश्न
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
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उत्तर
The equations can be written as follows:
y = 2 - x
y = `(1)/(2)(x - 5)`
y = `- x/(3)`
First prepare a table as follows:
| X | Y = 2 - x | Y = `(1)/(2)(x - 5)` | Y = `-x/(3)` |
| - 1 | 3 | - 3 | `(1)/(3)` |
| 0 | 2 | `-(5)/(2)` | 0 |
| 1 | 1 | - 2 | `-(1)/(3)` |
Thus the graph can be drawn as follows:

From the graph it is clear that the equation of lines are passes through the same point.
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संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
y = 0
Draw the graph for the linear equation given below:
3x + 2y = 0
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
Draw a graph of each of the following equations: y = `(5)/(2) xx + (2)/(5)`
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
