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प्रश्न
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
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उत्तर
The equations can be written as follows:
y = 2 - x
y = `(1)/(2)(x - 5)`
y = `- x/(3)`
First prepare a table as follows:
| X | Y = 2 - x | Y = `(1)/(2)(x - 5)` | Y = `-x/(3)` |
| - 1 | 3 | - 3 | `(1)/(3)` |
| 0 | 2 | `-(5)/(2)` | 0 |
| 1 | 1 | - 2 | `-(1)/(3)` |
Thus the graph can be drawn as follows:
From the graph it is clear that the equation of lines are passes through the same point.
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संबंधित प्रश्न
Draw the graph of the equation given below.
2x + y = 1
Draw the graph for the linear equation given below:
x + 3 = 0
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
Draw a graph of the equation 2x + 3y + 5 = 0, from the graph find the value of:
(i) x, when y = -3
(ii) y, when x = 8
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
