Advertisements
Advertisements
प्रश्न
Draw a graph of each of the following equations: x = -3y
Advertisements
उत्तर
x = -3y
When y = 1, x = -3(1) = -3
When y = 0, x = -3(0) = 0
When y = -2, x = -3(-2) = 6
| x | -3 | 0 | 6 |
| y | 1 | 0 | -2 |
Plotting the points (-3, 1), (0, 0) and (6, -2), we get a line AB as shown in the figure.
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
3x - y = 0
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
x = 0
Draw the graph for the linear equation given below:
y = 2x + 3
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = x - 3
y = - x + 5
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
