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प्रश्न
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = x - 3
y = - x + 5
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उत्तर
To draw the graph of y = x - 3 and y = - x + 5 follows the steps:
First, prepare a table as below:
| X | - 1 | 0 | 1 |
| Y = x - 3 | - 4 | -3 | - 2 |
| Y = - x + 5 | 6 | 5 | 4 |
Now sketch the graph as shown:
From the graph it can verify that the lines are perpendicular.
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
The graph of 3x + 2y = 6 meets the x=axis at point P and the y-axis at point Q. Use the graphical method to find the co-ordinates of points P and Q.
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Draw a graph of each of the following equations: 3x - 2y = 6
Draw a graph of each of the following equations: x = -3y
Draw a graph of the equation 2x - 3y = 15. From the graph find the value of:
(i) x, when y = 3
(ii) y, when x = 0
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
