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प्रश्न
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
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उत्तर
First draw the graph as follows:
This is a right triangle.
Thus the area of the triangle will be:
A = `(1)/(2) xx "base" xx "altitude"`
= `(1)/(2) xx (9)/(2) xx 3`
= `(27)/(4)`
= 6.75 sq.units
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संबंधित प्रश्न
Draw the graph of the equation given below.
3x - y = 0
Draw the graph for the linear equation given below:
y = - 2x
Draw the graph for the linear equation given below:
y = x
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: 2x + 3y = 12
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
