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प्रश्न
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
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उत्तर
First draw the graph as follows:
This is a right triangle.
Thus the area of the triangle will be:
A = `(1)/(2) xx "base" xx "altitude"`
= `(1)/(2) xx (9)/(2) xx 3`
= `(27)/(4)`
= 6.75 sq.units
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संबंधित प्रश्न
Draw the graph of the equation given below.
3x - y = 0
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
5x+ y = 0.
Draw the graph for the linear equation given below:
y = `4x - (5)/(2)`
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
