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प्रश्न
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
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उत्तर
`(x - 2)/(3) - (y + 1)/(2)` = 0
⇒ `(x - 2)/(3) - (y + 1)/(2)`
⇒ 2(x - 2) = 3(y + 1)
= 2x - 4 = 3y + 3
⇒ 3y = 2x - 7
⇒ y = `(2x - 7)/(3)`
When x = 2, y = `(2(2) - 7)/(3)` = -1
When x = -1, y = `(2(-1) - 7)/(3)` = -3
When x = -2.5, y = `(2(-2.5) - 7)/(3)` = 4
| x | 2 | -1 | -2.5 |
| y | -1 | -3 | -4 |
Plotting the points (2, -1), (-1, -3) and (-2.5, -4), we get a line AB as shown in the figure.
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
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(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
Draw a graph of each of the following equations: 3x - 2y = 6
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Draw a graph of the equation 2x + 3y + 5 = 0, from the graph find the value of:
(i) x, when y = -3
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