Advertisements
Advertisements
प्रश्न
Draw a graph of each of the following equations: 3y + 2x = 11
Advertisements
उत्तर
3y + 2x = 11
⇒ 3y = 11 - 2x
⇒ y = `(11 - 2x)/(3)`
When x = 1, y = `(11 -2(1))/(3)` = 3
When x = -2, y = `(11 -2(-2))/(3)` = 5
When x = -5, y = y = `(11 -2(-5))/(3)` = 7
| x | 1 | -2 | -5 |
| y | 3 | 5 | 7 |
Plotting the points (1, 3), (-2, 5) and (-5, 7), w get a line AB as shown in the figure.
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
3x - y = 0
Draw the graph of the equation given below.
2x + y = 1
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
x = 0
Draw the graph for the linear equation given below:
y = - x + 4
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
