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प्रश्न
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
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उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y | 2 | `(3)/(2)` | 1 |
Thus the graph can be drawn as shown:
(i) For y = 3 we have x = - 3
(ii) For y = - 2 we have x = 7
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
y = - 2x
Draw the graph for the linear equation given below:
3x + 2y = 0
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the equation given below:
2x - 5y = 10
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
Draw the graph of the lines represented by the equations x + y = 4 and 2x - y = 2 on the same graph. Find the coordinates of the point where they intersect
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
