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प्रश्न
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
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उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y | 2 | `(3)/(2)` | 1 |
Thus the graph can be drawn as shown:
(i) For y = 3 we have x = - 3
(ii) For y = - 2 we have x = 7
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संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
2x - 7 = 0
Draw the graph for the linear equation given below:
2y - 5 = 0
Draw the graph for the linear equation given below:
3x + 2y = 0
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
