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प्रश्न
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
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उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y | 2 | `(3)/(2)` | 1 |
Thus the graph can be drawn as shown:
(i) For y = 3 we have x = - 3
(ii) For y = - 2 we have x = 7
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संबंधित प्रश्न
Draw the graph of the equation given below.
3x - y = 0
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x = 0
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x + 2y = 0
Draw the graph for the linear equation given below:
y = - x + 4
Draw the graph for the each linear equation given below:
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Draw the graph for the equation given below:
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Find if the following points are collinear or not by using a graph:
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(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: 3x - 2y = 6
Draw a graph of each of the following equations: 3y + 2x = 11
