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प्रश्न
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
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उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y | 2 | `(3)/(2)` | 1 |
Thus the graph can be drawn as shown:
(i) For y = 3 we have x = - 3
(ii) For y = - 2 we have x = 7
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संबंधित प्रश्न
Draw the graph for the linear equation given below:
3x + 2y = 0
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
`(x - 1)/(3) - (y + 2)/(2) = 0`
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
(ii) y, when x = 2
Draw the graph of the lines y = x + 2, y = 2x - 1 and y = 2 from x = -3 to 4, on the same graph paper. Check whether the lines drawn are parallel to each other.
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
Draw the graph of the lines represented by the equations 2x - y = 8 and 4x + 3y = 6 on the same graph. Find the co-ordinates of the point where they intersect.
