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Question
Draw the graph of equation x + 2y - 3 = 0. From the graph, find:
(i) x1, the value of x, when y = 3
(ii) x2, the value of x, when y = - 2.
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Solution
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y | 2 | `(3)/(2)` | 1 |
Thus the graph can be drawn as shown:
(i) For y = 3 we have x = - 3
(ii) For y = - 2 we have x = 7
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