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प्रश्न
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
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उत्तर
First draw the graph as follows:
This is a right triangle.
Thus the area of the triangle will be:
A = `(1)/(2) xx "base" xx "altitude"`
= `(1)/(2) xx (9)/(2) xx 3`
= `(27)/(4)`
= 6.75 sq.units
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संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
y = - x
Draw the graph for the linear equation given below:
y = - 2x
Draw the graph for the linear equation given below:
y = 2x + 3
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
y = `4x - (5)/(2)`
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the equation given below:
`(2x - 1)/(3) - (y - 2)/(5) = 0`
Draw a graph of the equation 2x + 3y + 5 = 0, from the graph find the value of:
(i) x, when y = -3
(ii) y, when x = 8
Draw the graph of the lines represented by the equations x + y = 4 and 2x - y = 2 on the same graph. Find the coordinates of the point where they intersect
