Advertisements
Advertisements
प्रश्न
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Advertisements
उत्तर
First prepare a table as follows:
| x | -1 | 0 | 1 |
| y | `-(5)/(6)` | `(2)/(3)` | `(13)/(6)` |
Thus the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
y = 0
Draw the graph for the linear equation given below:
y = 3x
Draw the graph for the equation given below:
3x + 2y = 6
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
Draw the graph of the lines represented by the equations 2x - y = 8 and 4x + 3y = 6 on the same graph. Find the co-ordinates of the point where they intersect.
