Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
Advertisements
उत्तर
The equation will become:
5x - 2y = 17
First prepare a table as follows:
| x | - 1 | 0 | 1 |
| y | - 11 | `-(17)/(2)` | - 6 |
Thus the graph can be drawn as follows:

APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
x + 2y = 0
Draw the graph for the linear equation given below:
y = - x + 4
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
3x − (5 − y) = 7
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: `(2x)/(5) + y/(2)` = 1
Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
(ii) y, when x = 2
Draw the graph of the lines represented by the equations x + y = 4 and 2x - y = 2 on the same graph. Find the coordinates of the point where they intersect
