Advertisements
Advertisements
प्रश्न
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
Advertisements
उत्तर
First prepare a table as follows:
| x | - 1 | 0 | 1 |
| y | `-(1)/(5)` | `-(2)/(5)` | `-(3)/(5)` |
Thus the graph can be drawn as follows:
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
2x + y = 1
Draw the graph for the linear equation given below:
y - 2 = 0
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
x = - 2y
Draw the graph for the linear equation given below:
y = 2x + 3
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = x - 3
y = - x + 5
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: y = `(5)/(2) xx + (2)/(5)`
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
