Advertisements
Advertisements
प्रश्न
Draw the graph of the equation given below.
2x + y = 1
Advertisements
उत्तर
The equation of the given line is 2x + y = 1.
∴ 2x + y = 1
⇒ y = 1 − 2x ...(1)
Putting x = 0 in (1), we get
y = 1 − 2 × 0
y = 1 − 0
y = 1
Putting x = 1 in (1), we get
y = 1 − 2 × 1
y = 1 − 2
y = −1
Putting x = −1 in (1), we get
y = 1 − 2 × (−1)
y = 1 + 2
y = 3
Putting x = 2 in (1), we get
y = 1 − 2 × 2
y = 1 − 4
y = −3
These values can be represented in the table in the form of ordered pairs as follows:
| x | 0 | 1 | -1 | 2 |
| y | 1 | -1 | 3 | -3 |
| (x, y) | (0, 1) | (1, -1) | (-1, 3) | (2, -3) |

∴ The line is the graph of the equation 2x + y = 1.
APPEARS IN
संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph of the equation given below.
3x - y = 0
The following distribution gives the daily income of 50 workers of a factory.
| Daily income (in ₹) | 200-220 | 220-240 | 240-260 | 260-280 | 280-300 |
| Number of workers | 12 | 14 | 8 | 6 | 10 |
Convert the distribution above to a 'less than type' cumulative frequency distribution and draw its ogive.
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
y = x
Draw the graph for the linear equation given below:
5x+ y = 0.
Draw the graph for the linear equation given below:
4x - y = 0
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = 3x - 1
y = 3x + 2
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Draw a graph of each of the following equations: 5x + 2y = 16
Draw a graph of each of the following equations: x = -3y
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
