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प्रश्न
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: 2x + 3y = 12
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उत्तर
2x + 3y = 12
⇒ 3y = 12 - 2x
⇒ y = `4 - (2)/(3) x`
When x = 3, y = `4 - (2)/(3)(3)` = 2
When x = -3, y = `4 - (2)/(3)(-3)` = 6
When x = 6, y = `4 - (2)/(3)(6)` = 0
| x | 3 | -3 | 6 |
| y | 2 | 6 | 0 |
Plotting the points (3, 2), (-3, 6) and (6, 0), we get a line segment as shown in the figure.
The line meets the x-axis at (6, 0) and y-axis at (0, 4).
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संबंधित प्रश्न
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
3y + 5 = 0
Draw the graph for the linear equation given below:
y = 0
Draw the graph for the linear equation given below:
y = x
Draw the graph for the linear equation given below:
y = `(2x)/(3) - 1`
Draw the graph for the linear equation given below:
y = `4x - (5)/(2)`
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Draw a graph of each of the following equations: `(x - 2)/(3) - (y + 1)/(2)` = 0
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
