Advertisements
Advertisements
प्रश्न
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
Advertisements
उत्तर
To draw the graph of 3x + 4y = 24 and `x/(4) + y/(3) = 1` follows the steps:
First prepare a table as below
| X | -1 | 0 | 1 |
| Y = `-(3)/(4) xx + 6` | `(27)/(4)` | 6 | `(21)/(4)` |
| Y = `-(3)/(4) xx + 3` | `(15)/(4)` | 3 | `(9)/(4)` |
Now sketch the graph as shown:
From the graph it can verify that the lines are parallel.
APPEARS IN
संबंधित प्रश्न
Draw the graph for the linear equation given below:
x = 3
Draw the graph for the linear equation given below:
y + 6 = 0
Draw the graph for the linear equation given below:
y = 3x
Draw the graph for the linear equation given below:
y = `4x - (5)/(2)`
Draw the graph for the linear equation given below:
x - 3 = `(2)/(5)(y + 1)`
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
Use the graphical method to show that the straight lines given by the equations x + y = 2, x - 2y = 5 and `x/(3) + y = 0` pass through the same point.
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
Draw a graph for each of the following equations and find the coordinates of the points where the line drawn meets the x-axis and y-axis: 2x + 3y = 12
Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
(ii) y, when x = 2
