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प्रश्न
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
3x + 4y = 24
`x/(4) + y/(3) = 1`
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उत्तर
To draw the graph of 3x + 4y = 24 and `x/(4) + y/(3) = 1` follows the steps:
First prepare a table as below
| X | -1 | 0 | 1 |
| Y = `-(3)/(4) xx + 6` | `(27)/(4)` | 6 | `(21)/(4)` |
| Y = `-(3)/(4) xx + 3` | `(15)/(4)` | 3 | `(9)/(4)` |
Now sketch the graph as shown:
From the graph it can verify that the lines are parallel.
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संबंधित प्रश्न
Draw the graph of the equation given below.
2x + y = 1
Draw the graph for the linear equation given below:
x - 5 = 0
Draw the graph for the linear equation given below:
y = 4
Draw the graph for the linear equation given below:
3x + 2y = 0
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Draw the graph of equation `x/(4) + y/(5) = 1` Use the graph drawn to find:
(i) x1, the value of x, when y = 10
(ii) y1, the value of y, when x = 8.
Draw a graph of each of the following equations: 5x + 2y = 16
Draw a graph of each of the following equations: y = `(3)/(5) x - 1`
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
Draw a graph of the equation 2x - 3y = 15. From the graph find the value of:
(i) x, when y = 3
(ii) y, when x = 0
