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प्रश्न
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
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उत्तर
To draw the graph of 2x - 3y = 6 and `x/(2) + y/(3) = 1` follows the steps:
First prepare a table as below:
| X | -1 | 0 | 1 |
| Y = `(2)/(3) xx 2` | `-(8)/(3)` | -2 | `-(4)/(3)` |
| Y = `-(3)/(2) xx + 3` | `(9)/(2)` | 3 | `(3)/(2)` |
Now sketch the graph as shown:
From the graph it can verify that the lines are perpendicular.
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संबंधित प्रश्न
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| Number of workers | 12 | 14 | 8 | 6 | 10 |
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Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
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Draw a graph of the equation 5x - 3y = 1. From the graph find the value of:
(i) x, when y = 8
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