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प्रश्न
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
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उत्तर
To draw the graph of 2x - 3y = 6 and `x/(2) + y/(3) = 1` follows the steps:
First prepare a table as below:
| X | -1 | 0 | 1 |
| Y = `(2)/(3) xx 2` | `-(8)/(3)` | -2 | `-(4)/(3)` |
| Y = `-(3)/(2) xx + 3` | `(9)/(2)` | 3 | `(3)/(2)` |
Now sketch the graph as shown:

From the graph it can verify that the lines are perpendicular.
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संबंधित प्रश्न
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
Draw the graph of the equation given below.
x + y = 2
Draw the graph for the linear equation given below:
x = - 2y
Draw the graph for the equation given below:
3x + 2y = 6
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
Draw a graph of each of the following equations: 5x + 2y = 16
Draw a graph of each of the following equations: x + y - 3 = 0
Draw a graph of the equation 3x - y = 7. From the graph find the value of:
(i) y, when x = 1
(ii) x, when y = 8
Draw the graph of the lines represented by the equations 3x - 2y = 4 and x + y = 3 on the same graph. Find the coordinates of the point where they intersect. State, whether the lines are perpendicular to each other.
Draw the graph of the lines represented by the equations 2x - y = 8 and 4x + 3y = 6 on the same graph. Find the co-ordinates of the point where they intersect.
