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प्रश्न
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
2x - 3y = 6
`x/(2) + y/(3) = 1`
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उत्तर
To draw the graph of 2x - 3y = 6 and `x/(2) + y/(3) = 1` follows the steps:
First prepare a table as below:
| X | -1 | 0 | 1 |
| Y = `(2)/(3) xx 2` | `-(8)/(3)` | -2 | `-(4)/(3)` |
| Y = `-(3)/(2) xx + 3` | `(9)/(2)` | 3 | `(3)/(2)` |
Now sketch the graph as shown:

From the graph it can verify that the lines are perpendicular.
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संबंधित प्रश्न
Draw the graph of the equation given below.
3x - y = 0
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x + 3 = 0
Draw the graph for the linear equation given below:
x = 0
Draw the graph for the linear equation given below:
y = x
Draw the graph for the linear equation given below:
5x+ y = 0.
For the pair of linear equations given below, draw graphs and then state, whether the lines drawn are parallel or perpendicular to each other.
y = x - 3
y = - x + 5
Draw the graph of equation 3x – 4y = 12. Use the graph drawn to find:
- y1, the value of y, when x = 4.
- y2, the value of y, when x = 0.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
Draw a graph of each of the following equations: x + 6y = 15
Draw a graph of each of the following equations: 2(x - 5) = `(3)/(4)(y - 1)`
